## IAS EXAM PUZZLE QUESTIONS

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Only 1% Students solved it (IAS exam)

3+5+6=151872

5+5+6=253094

5+6+7=303585

5+5+3=251573

then 9+4+7=_______?

Time to check your intellect… All the best!

So were you able to solve the riddle? Leave your answers in the comment section below.

SOLUTION OF THIS PUZZLE

The solution to the first 4 digits is pretty straight forward, and I am sure most of you must have easily got it.

It works out to be a+b+c = (a*b)(a*c)??

The last 2 digits are really tough to crack…

Here’s how you do it. Reverse of {(a×b)+(a×c)-c}

So the number would (a×b),(a×c),{(a×b)+(a×c)-c}reverse.

So for 1st one: 3+5+6=151872;
axb = 3×5 = 15; axc = 3×6 = 18;
{(a×b)+(a×c)-c} = ((3×5)+(3×6)-6} = 27
— Reverse of 27 is 72

So 9+4+7=_______?

axb = 9×4 = 36;
axc = 9×7 = 63;
{(a×b)+(a×c)-c} = ((9×4)+(9×7)-7} = (36+63-7)=92
— Reverse of 92 is 29.